An ice skater of mass m = 60 kg coasts at a speed of v = 0.8 m/s past a pole. at the distance of closest approach, her center of mass is r1 = 0.45 m from the pole. at that point she grabs hold of the pole.

a. what is the skater's angular speed when she first grabs the pole? rad/s
b. what is the skater's angular speed after she now pulls her center of mass to a distance of r_2 = 0.46 m from the pole? rad/s

1.78 rad/s

1.70344 rad/s

Explanation:

v = Velocity = 0.8 m/s

m = Mass of person = 60 kg

= Distance between center of mass of person and pole = 0.45 m

= New distance between center of mass of person and pole = 0.46 m

I = Moment of inertia

Angular speed is given by

The angular speed is 1.78 rad/s

In this system the angular momentum is conserved

The new angular speed is 1.70344 rad/s

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