Water is discharged from a pipeline at a velocity v (in ft/sec) given by v = 1306p(1/2), where p is the pressure (in psi). if the water pressure is changing at a rate of 0.354 psi/sec, find the acceleration (dv/dt) of the water when p = 36.0 psi

Explanation:

Note that acceleration is the rate change of velocity i.e

.

Since the velocity is giving as a variable dependent on the pressure, we have to differentiate implicitly both side with respect to time,i.e

if we substitute value for the pressure as giving in the question and also since the rate change of pressure is 0.354psi/sec, we have

temp rises, and expansion