A1280-kg car pulls a 350-kg trailer. the car exerts a horizontal force of 3.6 × 10^3 n against the ground in order to accelerate. what force does the car exert on the trailer? assume an effective friction coefficient of 0.15 for the trailer.

1176 N

Explanation:

We are given that

Mass of car=1280 kg

Mass of trailer==350 kg

Car exerts a horizontal force against the ground =N

Coefficient of friction=

We have to find the force exerted by car  on the trailer.

Substitute the values then we get

Force exert on the trailer

Hence, the car exerts force on the trailer=1176 N

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .