Aperson has a reasonable chance of surviving an automobile crash if the deceleration is no more than 30 g’s.
(a) calculate the force on a 65-kg person accelerating at this rate.
(b) what distance is traveled if brought to rest at this rate from 95 km/h?

19129.5 N

1.1831 m

Explanation:

m = Mass of person = 65 kg

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration = 30g

g = Acceleration due to gravity = 9.81 m/s²

Force is given by

The force on the person is 19129.5 N

The distance traveled if brought to rest is 1.1831 m

a is the best answer your welcome