If a trapezoidal channel has side slopes of 1: 1, hydraulic depth is 5 feet, the bottom width is 8 feet, flow is 2,312 cubic feet per seconds and the manning's "n" is 0.013, what is the slope of the channel? g

Explanation:

given,

side slope = 1 : 1

hydraulic depth(y) = 5 ft

bottom width (b)= 8 ft

x = 1

Q = 2,312 ft³/s

n = 0.013

slope of channel = ?

R = 4.69 m

using manning's equation

S = 0.406

the answer is b i think

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