Assume that each particle contains only combinations of the quarks u, d, and s and the antiquarks u¯, d¯,

part a deduce the quark content of a particle with charge +e, baryon number 0, and strangeness +1.
view available hint(s) deduce the quark content of a particle with charge +e, baryon number 0, and strangeness +1. dds us¯ u¯s uus usd
part b deduce the quark content of a particle with charge +e, baryon number −1, and strangeness +1.
view available hint(s) deduce the quark content of a particle with charge +e, baryon number 1, and strangeness +1. dds us¯ uus d¯d¯s¯ usd
part c deduce the quark content of a particle with charge 0, baryon number +1, and strangeness −2.

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

b.

explanation:

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .