100 g of liquid nitrogen at its boiling point of 77 k is stirred into a beaker containing 500 g of 15°c water.

if the nitrogen leaves the solution as soon as it turns to gas, how much water freezes?

the heat of vaporization of nitrogen is 48 cal/g and that of water is 80 cal/g.

a. noneb. 29 gc. 68 gd. 109 g

(a). none

Explanation:

Heat gained by nitrogen = Heat lost by water

Q₁ = Q₂ + Q₃ Equation 1

Where Q₁ = heat required for nitrogen to vaporize, Q₂ = heat required for to change temperature from 15 °C to 0 °C, Q₃ = heat required for water to vaporize.

Q₁ = m₁l₁ Equation 2

Q₂ =cm₂(T₁-T₂) Equation 3

Q₃ = m₃l₂ Equation 4

Note: For the water to freeze, Q₁ > Q₂

Where m₁ = mass of nitrogen, m₂ = mass of water in liquid state, m₃ = mass of water that freezes, l₁ = heat of vaporization of nitrogen, l₂ =  heat of vaporization of water, c = specific heat capacity of water, T₁ = initial temperature of water, T₂ = Final Temperature of water( Temperature at freezing point)

Given: m₁ = 100 g, m₂ = 500 g, T₁ = 15 °C, T₂ = 0 °C, l₁ = 48 cal/g, 80 cal/g

Constant: c = 1.00 cal/g.k

Substituting these values into equation 2, 3 and equation 4

Q₁ = 100 × 48 = 4800 Cal.

Q₂ = 1 × 500 × (15-0)

Q₂ = 7500 cal

Q₃ = m₃(80) = 80m₃ Cal

Substituting the values of Q₁, Q₂ and Q₃ into Equation 1

4800 = 7500 + 80m₃

Collecting like terms

80m₃ = 4800 - 7500

m₃ = -2700/80

m₃ = no ice formed, Because the mass of a substance can not be negative.

Therefore, The nitrogen evaporates but does not cause any change in temperature.

The right option is (a) none

we need to know the time interval during which the force acts. impulse of force = momentum change

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.