Agas is compressed at a constant pressure of 0.643 atm from 5.46 l to 2.01 l. in the process, 564 j of energy leaves the gas by heat. what is the work done on the gas? remember: 1 atm = 1.013 × 105 pa. answer in units of j. 008 (part 2 of 2) 10.0 points what is the change in its internal energy? answer in units of j.

Part 1)

- 224.6 J

Part 2)

- 339.4 J

Explanation:

= Constant pressure acting on gas = 0.643 atm = (0.643) (1.013 x 10⁵) Pa = 0.651 x 10⁵ Pa

= initial volume = 5.46 L = 0.00546 m³

= final volume = 2.01 L = 0.00201 m³

Work done on the gas is given as

Part 2)

= Change in the internal energy

= Heat energy escaped = - 564 J

Using First law of thermodynamics

1 a

2 b

3 b

4 d

5 d

6 d

explanation:

d is the correct answer