Three identical particles, q1, q2, and q3, each with charge q = 5.00 μc, are placed along a circle of radius r = 2.00 m at angles 90, 180, and 270 degrees from the positive x-axis, respectively.
what is the resultant electric field at the center of the circle, point o? all angles are measured counterclockwise from the positive x-axis.

11250 N/C

Direction: 0 deg counterclockwise from positive x-axis

Explanation:

= magnitude of charge on each particle = 5 μC =  5 x 10⁻⁶ C

= distance of each particle from center of circle = 2 m

= Magnitude of electric field at the center by each particle

Magnitude of electric field at the center by each particle is given as

inserting the values

From the diagram , we see that being equal and opposite, the electric fields due to charge q₁ and q₃ cancel out.

So net electric field at center is only due to charge q₂ direction towards positive x-direction

So

= Resultant electric field = 11250 N/C

Direction: 0 deg counterclockwise from positive x-axis

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

i think the answer is a, hope this : )