In one cycle a heat engine absorbs 450 j from a high-temperature reservoir and expels 290 j to a low-temperature reservoir. if the efficiency of this engine is 55% of the efficiency of a carnot engine, what is the ratio of the low temperature to the high temperature in the carnot engine?

So the ratio will be

Explanation:

We have given heat engine absorbs 450 joule from high temperature reservoir

So

As the heat engine expels 290 j

So work done W = 290 J

We know that efficiency

It is given that efficiency of the engine only 55 % of Carnot engine

So efficiency of Carnot engine

Efficiency of Carnot engine is

0.64

Explanation:

QH = 450 J

Qc = 290 J

efficiency, η = 55 %

Let Tc be the low temperature and TH be the high temperature.

According to the Carnot's theorem

So, the ratio is 0.64.