Two separate speakers each produce 524 hz notes (the c above middle c)in air on earth. the sounds would be perfectly in phase if the speakers were placed next to each other. if both speakers are pointing in the same direction and directly at you, then how far apart would they have to be placed in order for you to experience total deconstructive wave interference

Explanation:

Frequency of sound = 524 Hz

wavelength of sound λ = velocity / frequency

= 340 / 524

λ = .6488 m

When sound from two sources reach a point simultaneously with a phase difference of π or path difference of λ/2 , or its odd multiple  they overlap to give rise to destructive interference

so for destructive interference

path difference = ( 2n+1) λ/2

Here λ/2 = .6488 /2

= .3244 m

or 32.44 cm

So the loudspeaker must be placed with a gap of 32.44 cm or its odd multiple

when insulating materials rub against each other, they may become electrically charged . electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. the material that gains electrons becomes negatively charged. the material that loses electrons is left with a positive charge.

i think it's 35 meters