Atruck travels 1430 m uphill along a road that makes a constant angle of 5.76◦ with the horizontal.
find the magnitude of the truck’s horizon- tal component of displacement.
answer in units of m.

The horizontal component of displacement is d' = 1422.7 m

Explanation:

Given data,

The distance covered by the truck, d = 1430 m

The angle formed with the horizontal, Ф = 5.76°

The displacement is a vector quantity.

The horizontal component of displacement is given by,

                                 d' = d cos Ф

                                     = 1430 cos 5.76°

                                     = 1422.7 m

Hence, the horizontal component of displacement is d' = 1422.7 m

the correct choice is a .

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