3. a vehicle is on a hill that has a 20 degree angle below the horizontal. an
irresponsible driver leaves the vehicle in neutral. the vehicle rolls backwards
toward the edge of the cliff. the acceleration is 2.37 m/s2 and the distance
traveled is 55m before the vehicle reaches the edge of the cliff.
a. how much time will the vehicle be in the air after leaving the cliff?
b. how far horizontally will the vehicle be away from the cliff when it lands?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j