If a space ship is traveling with a constant acceleration of 75 m/s^2 and travels for three weeks, how far did it travel and what was it's velocity before  it stopped?

The final velocity of the ship is, v = 136050000 m/s

The total distance covered, s = 6.94 x 10¹⁷ m

Explanation:

Given data,

The constant acceleration of the space ship, a = 75 m/s²

The time period of the space ship acceleration is t = 3 weeks

                                                                                   t = 1.814 x 10⁶ s

The initial velocity of the ship is u = 0 m/s

The final velocity of the ship is,

                                    v = u + at

                                       = 0 + 75 (1.814 x 10⁶)

                                       = 136050000 m/s

The distance space ship traveled, can be calculated from the second equation of motion.

                                   s = ut + ½ at²

                                      = 0 + ½ 75 (136050000)²

                                       = 6.94 x 10¹⁷ m

Hence, the total distance covered, s = 6.94 x 10¹⁷ m

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

h o h o hope you have a merry christmas!