Solve for the tension in the left rope, tl, in the special case that x=0. be sure the result checks with your intuition. express your answer in terms of w and the dimensions l and x. not all of these variables may show up in the solution.

at x=0

=W*L/L

and

=W-

Explanation:

Solve for the tension in the left rope, TL, in the special case that x=0. Be sure the result checks with your intuition. Express your answer in terms of W and the dimensions L and x. Not all of these variables may show up in the solution.

moments is the product of force and the perpendicular distance in line of the action of the given force

from the principle of moments which states that the sum of clockwise moments ,must be equal to the sum of anticlockwise moments.

also, sum of upward forces must be equal to sum of downward forces

Going by the aforementioned,

taking moments about

W*(l-x)=*(L)

=W*(L-x)/(L)..............1

at x=0

=W*L/L

also

+ =W

=W-

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2