Starting from rest at a height equal to the radius of the circular track, a block of mass 24 kg slides down a quarter circular track under the influence of gravity with friction present (of coefficient µ). the radius of the track is 15 m. the acceleration of gravity is 9.8 m/s 2 .starting from rest at a height equal to the radius of the circular track, a block of mass 24 kg slides down a quarter circular track under the influence of gravity with friction present (of coefficient µ). the radius of the track is 15 m. the acceleration of gravity is 9.8 m/s 2 . if the kinetic energy of the block at the

bottom of the track is 3900 j, what is the

work done against friction?

answer in units of j.

The work done against friction is 372 joules

Explanation:

It is given that,

Mass of block, m = 24 kg

Radius of the track, r = 15 m

Acceleration due to gravity,

If the kinetic energy of the block at the  bottom of the track is, 3900 J

Let P is the work done against friction. It is given by :

Here, h = r

P = 3528 J

Since it ends up with 3900 J, the work done is given by or the lost in energy will be :

W = 3900 - 3528

W = 372 joules

So, the work done against friction is 372 joules. Hence, this is the required solution.

where is the circuit diagram ?

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i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!