An irregularly shaped flat object of mass 2.00 kg is suspended from a point at a distance d from its center of mass and allowed to undergo simple harmonic motion in the vertical plane. the object has moment of inertia i = 1.28 kg · m2 about an axis passing through the point of suspension and perpendicular to the plane of the object. the frequency of this oscillatory motion is 0.660 hz. what is the distance d of the pivot point from the center of mass of the object?

1.12191 m

Explanation:

m = Mass of point = 2 kg

f = Frequency = 0.66 Hz

I = Moment of inertia = 1.28 kgm²

g = Acceleration due to gravity = 9.81 m/s²

For a compound pendulum the angular velocity is given by

The distance of the pivot point from the center of mass of the object is 1.12191 m

it about 600 mph from what i calculated

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.