Arace car accelerates uniformly at 11.3 m/s2. if the race car starts from rest how fast will it
be going after 6.7 seconds.

75.71 m/s

Explanation:

From equation of motion, acceleration is given by

where v is the final velocity, u is the initial velocity and t is time taken.

Making v the subject of the above formula

v=at+u

Substituting 6.7 s for time, t and 11.3 for a and taking u as zero since it starts from rest

v=11.3*6.7=75.71 m/s

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000