A92kg astronaut and a 1200kg satellite are at rest relative to the space shuttle. the astronaut pushes on the satellite, giving it a speed of 0.14m/s directly away from the shuttle. seven and a half seconds later the astronaut comes into contact with the shuttle. what was the initial distance from the shuttle to the astronaut?

13.7m

Explanation:

Since there's no external force acting on the astronaut or the satellite, the momentum must be conserved before and after the push. Since both are at rest before, momentum is 0.

After the push

Where is the mass of the astronaut, is the mass of the satellite, is the speed of the satellite. We can calculate the speed of the astronaut:

So the astronaut has a opposite direction with the satellite motion, which is further away from the shuttle. Since it takes 7.5 s for the astronaut to make contact with the shuttle, the distance would be

d = vt = 1.83 * 7.5 = 13.7 m

there are no correct statementd on the list of choices you provided.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer