For an rlc circuit in the limit of very high frequency, what is the effective behavior of the capacitor and the inductor in the circuit?

Explanation:

Given

In R-L-C circuit frequency is very high

Inductive Reactance for inductor is given by

Inductive Reactance for Capacitor is given by

as frequency becomes too high then will become very large and and will be approximately zero .

In other words inductor behave as a very high resistance and Capacitor behaves as very small resistance                            

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

i think the answer is a, hope this : )