2. three charged particles are placed at the corners of an equilateral triangle of side 1.20 m. the charges are +7.0μc, -8.0 μc and -6.0 μc. calculate the net force on charge 1 due to the other two charges in unit vector notation. give values for the magnitude and direction of the force, too.

0.53 N, 25.6°

Explanation:

side of triangle, a = 1.2 m

q = 7 μC

q1 = - 8 μC

q2 = - 6 μC

Let F1 be the force between q and q1

By using the coulomb's law

F1 = 0.35 N

Let F2 be the force between q and q2

By using the coulomb's law

F2 = 0.26 N

Write the forces in the vector form

Net force

Magnitude of the force

F = 0.53 N

Direction of force with x axis

θ = 25.6°

double the distance = divide strength by 4

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