A1.00 kg block of aluminum is heated at atmospheric pressure so that its temperature increases from 22.0°c to 40.0°c.
(a) find the work done on the mj(b) find the energy added to it by kj(c) find the change in its internal kj

(a). The work done on the aluminum is -48.6 mJ.

(b). The energy added to it by heat is 16.58 kJ.

(c). The change in its internal energy is 1.658 kJ.

Explanation:

Given that,

Mass of block = 1.00 kg

Initial pressure =22.0°C

Final pressure = 40.0°C

(a). We need to calculate the work done on the aluminum

Using formula of work done

Here,

Put the value into the formula

(b). We need to calculate the energy added to it by heat

Using formula of heat

Put the value into the formula

(c). We need to calculate the change in its internal energy

Using formula of internal energy

Put the value into the formula

Hence, (a). The work done on the aluminum is -48.6 mJ.

(b). The energy added to it by heat is 16.58 kJ.

(c). The change in its internal energy is 1.658 kJ.

the answer is 3.1 his answer is wrong mines is right