Ahockey player uses her hockey stick to exert a force of 6.81 n on a stationary hockey puck. the hockey puck has a mass of 165 g. what is the acceleration of the hockey puck?

a. 0.13 m/s2

b. 11.3 m/s2

c. 21.3 m/s2

d. 31.3 m/s2

e. 41.3 m/s2

41.3 m/s^2 option (e)

Explanation:

force, F = 6.81 N

mass, m = 165 g = 0.165 kg

Let a be the acceleration of the puck.

Use newtons' second law

Force = mass x acceleration

6.81 = 0.165 x a

a = 41.27 m/s^2

a = 41.3 m/s^2

Thus, the acceleration of the puck is 41.3 m/s^2.

small = small current large mag large current

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .