A75 kg man is standing at rest on ice while holding a 4kg ball. if the man throws the ball at a velocity of 3.50 m/s forward, what will his resulting velocity be?

His resulting velocity will be 0.187 m/s backwards.

Explanation:

Given:

Mass of the man is,

Mass of the ball is,

Initial velocity of the man is,

Initial velocity of the ball is,

Final velocity of the ball is,

Final velocity of the man is,

In order to solve this problem, we apply law of conservation of momentum.

It states that sum of initial momentum is equal to the sum of final momentum.

Momentum is the product of mass and velocity.

Initial momentum = Initial momentum of man and ball

Initial momentum =

Final momentum = Final momentum of man and ball

Final momentum =

Now, initial momentum = final momentum

The negative sign implies backward motion of the man.

Therefore, his resulting velocity is 0.187 m/s backwards.

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete