A70.0 kg stuntman is attached to a bungee cord with an unstretched length of 15.0 m. he jumps off a bridge spanning a river from a height of 50.0 m. when he finally stops, the cord has a stretched length of 44.0 m. treat the stuntman as a point mass, and disregard the weight of the bungee cord. assuming the spring constant of the bungee cord is 71.8 n/m, what is the total potential energy relative to the water when the man stops falling?

The total potential energy is 34.307 kJ

Solution:

As per the question:

Mass of the stuntman, m = 70.0 kg

Length of the unstretched cord, l = 15.0 m

Height of the cord, H = 50.0 m

The stretched length of the cord,

Spring constant of the cord, k = 71.8 N/m

Now,

The total potential energy is given as the sum of gravitational potential energy and elastic potential energy:

The height attained, h = H - = 50.0 - 44.0 = 6.0 m

PE_{G} = mgh =    

Now, the elastic potential energy:

x = l - = 44.0 - 15.0 = 29.0 m

The Total Potential Energy:

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation:

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)