what is the resistance in a light bulb with a voltage of 25v and a current of 0.2a

R = 125Ω

Explanation:

Use the equation for voltage:

V = IR

V is voltage, in volts V

I is current, in amperes A

R is resistance, in ohms Ω

Substitute V for 25V and I for 0.2A

V = IR

(25V) = (0.2A)R  Isolate R for resistance. Divide both sides by 0.2

R = 125Ω

The resistance for the lightbulb is 125 Ω.

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