An 100kg object traveling at 50m/s collides (perfectly inelastic) with a 50kg object initially at rest. what is the sum of the momentum of both objects prior to the collision?

5000 kg.m/s

Explanation:

Before collision, momentum of 100 Kg is given by

p=mv where p is momentum, m is the mass of object and v is the velocity,

therefore, the momentum=100*50=5000 kg.m/s

The momentum of the 50 Kg is zero since it's at rest hence v=o

Total momentum before collision is therefore 5000+0=5000 kg.m/s

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~

increase masses, decrease separation