Asmall logo is embedded in a thick block of crown glass (n = 1.52), 4.70 cm beneath the top surface of the glass. the block is put under water, so there is 1.70 cm of water above the top surface of the block. the logo is viewed from directly above by an observer in air. how far beneath the top surface of the water does the logo appear to be?

The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

Where,

Depth of glass

Refraction index of water

Refraction index of glass

Refraction index of air

Depth of water

I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to

Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.