Vertical spring of force constantkhas a sortof catcher on the upper end, the lower endbeing fixed to a floor. the spring is initiallyneither stretched nor compressed. a massis dropped from some distance straight downonto the spring; upon hitting the catcher itcompresses the spring a distancesbefore com-ing to momentary rest.

in terms of these quantities, what was thekinetic energy of the mass the instant it hitthe spring catcher?

K = mg h

Explanation:

We will solve this exercise through energy conservation

Initial. Highest point

       Em₀ = U = m g (h + x)

Final. When the spring hits

        = K + U = K + mg x

       Em₀ =

       m g (h + x) = K + mgx

       mg h (h + x) –mgx = K

       K = mg h

We can also solve it with the points

Initial. Spring contact point

       Em₀ = K + U = K + m g x

Final. Maximum compression

        = = ½ k x²

       Emo =

       K + mg x = ½ k x²

       K = ½ k x² - mg x

iron would move it is magnetic there is a mag field around the current in the wire

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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