Alaser with wavelength d/8 is shining light on a double slit with slit separation 0.500 mm. this results in an interference pattern on a screen a distance l away from the slits. we wish to shine a second laser, with a different wavelength, through the same slits. what is the wavelength λ of the second laser that would place its second maximum at the same location as the fourth minimum of the first laser, if d = 0.500 mm?

0.000109375 m

Explanation:

d = Distance between grating = 0.5 mm

m = Order

Minima relation

For fourth order minima

For second maxima

From the two equations we get

The wavelength is 0.000109375 m

answer: 0.20

explanation: this can only be the answew because all the other measuremnets are not close

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).