Atypical home may require a total of 2.00*10^3kwh of energy per month. suppose you would like to obtain this energy from sunlight, which has an average daylight intensity of 1400 w/m^2 . assuming that sunlight is available 8.0h per day, 25 d per month (accounting for cloudy days), and that you have a way to store energy from your collector when the sun isn't shining, determine the smallest collector size that will provide the needed energy, given a conversion efficiency of 24% .

Smallest collector size≈30

Explanation:

Daily sunlight intensity = 1400.

For a collector of 24% efficiency, the absorption per day per

= 0.24*1400 = 336.

For 8 hours, 25days of available sunlight, energy absorbed by collector per metre square , will be = 8* 25 *336 = 67200wh.

This is the amount of sunlight energy which will be trapped by 1. of collector in a month.

To find how many metre square of collector is required to get 2*kwh, we simply divide the required energy by the amount absorbed per square metre.

Smallest size of collected needed =

=29.76

≈30

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//

conduct current i mean it makes sense