An automobile slows from 26 m/s to 18 m/s. its acceleration is
-2.0 m/s2. how much time does it take for the vehicle to slow
down?
a) 2.5s
b) 4.0 s
c) 1.55
(someone ^_^ i’m not a number person whatsoever)

a lot of it means it can be "burned" for energy and sold at one price. if it is scarce, the price will go up

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm