The distance between the points a and b on two equipotential lines with v1=5.2 v and v2=1.8 v is 2.8 cm. what is the average electric field (in volt/m) at the midpoint c expressed to one decimal place?

121.142 V/m

Explanation:

A and B are on two  equipotential line.

Equipotential line are imaginary lines in space along which the potential does not change.

to find electric field at the midpoint C

we use the formula

=

=

= 121.142 V/m

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the part of the wave he is travelling on is the crest