Abungee jumper with mass 58.5 kg jumps from a high bridge. after arriving at his lowest point, he oscillates up and down, reaching a low point seven more times in 45.0 s . he finally comes to rest 20.5 m below the level of the bridge. calculate the spring stiffness constant and the unstretched length of the bungee cord.

10.23077 m

55.88391 N/m

Explanation:

m = Mass of person = 58.5 kg

T = Time period =

k = Spring constant

g = Acceleration due to gravity = 9.81 m/s²

Time period is given by

The spring stiffness constant is 55.88391 N/m

The force on spring is given by

The unstreched length of the cord is 20.5-10.26923 = 10.23077 m

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explanation:

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.