A1 kg ball is dropped from the top of a cliff and falls with a constant acceleration due to gravity (9.8 m/s2). assume that effects of air resistance can be ignored. a.) by how much has the ball's gravitational potential energy changed after it has fallen

Gravitational potential Energy change of the ball after, 10m= 98J

Explanation:

A 1 kg ball is dropped from the top of a cliff and falls with a constant acceleration due to gravity (9.8 m/s2). Assume that effects of air resistance can be ignored. a.) By how much has the ball's gravitational potential energy changed after it has fallen by 10 m

Gravitational Potential Energy: This is the energy a body posses by virtue of it's position in a gravitational field. It is measured in Joules.

Gravitational potential Energy = Mass(m) × acceleration due to gravity (g) × Height(h) = mgh

Where m = 1kg, g = 9.8 m/s², h =10 m

∴ Gravitational potential Energy change of the ball after, 10m = 1  ×  9.8  ×  10 = 98 J

answera compound;