Jason takes off across level water on his jet-powered skis. the combined mass of jason and skis is 75 kg (the mass of the fuel is negligible). the skis have a thrust of 200 n and a coefficient of kinetic friction on water of 0.1. unfortunately, the skis run out of fuel after only 41 s. how far has jason traveled when he finally coasts to a stop?

r = 3858.7635 m

Explanation:

first we will use the law of newton as:

-mg+N = 0

N = mg

where m is the mass, g the gravity and N is the normal force, So:

N = (75)(9.8)

N = 735  

also, when the skis had fuel:

F- = ma

where F is the force of the skis, is the force by the kinetic friction and a is the aceleration.

so:

F- = ma

200N-(0.1)(735) = (75)a

is the coefficient of kinetic friction on water, therefore solving for a:

a = 1.687 m/s^2

so, with the aceleration we can find the velocity V of jason just after the skis run out of fuel as:

V = at

V = (1.687m/s^2)(41s)

V = 69.167 m/s^2

Where t is the time in which the skis run out of fuel. Now using the law of the conservation of energy we will find the distance as:

Initial Energy - Final Energy = Work of Friction

d = 2440.8m

that means that jason traveled 2440.8m after the skis run out of fuel.

Additionally, the distance x that jason traveled with fuel is calculated as:

x  =

x =

x = 1417.9235 m

Finally, Jason travel 3858.76 m when he finally coast to a stop. It is calculated as:

r = x + d

r = 1417.9235+2440.8

r = 3858.7635 m

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation: