An astronaut goes out for a "space-walk" at a distance above the earth equal to the radius of earth. what is her acceleration due to gravity at that point?
a) zero
b) g
c) g /2
d) g/4
e) g/2

d)

Explanation:

The acceleration due to gravity on the surface of the Earth is given as:

Where, 'G' is universal gravitational constant, 'M' is the mass of Earth, and 'R' is the radius of Earth.

Now, when the astronaut goes above the Earth equal to the radius of Earth, the distance between the center of Earth and the astronaut is twice the radius.

Therefore, new distance between the astronaut and Earth's center is '2R'.

Now, the acceleration due to gravity at point is given as:

Hence, her acceleration due to gravity at that point is

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

the temperature in kelvin of 2.0 dm3 of an ideal gas is doubled and its pressure is increased by a factor of four. what is the final volume of the gas