Atreasure hunter following a secret map
walks 13.8 km at 35.3° north of west to an old
tree stump, then turns and goes 17.6 km at
60.6° south of east to a large rock. find the
treasure hunter's final displacement.

answer:

19.02km

explanation:

as we apply head to tail rule suppose the man is at a walks upto b and then to c. we can find the direct path from a to c.

ac= ab+bc

but f=√fₓ² +fy²

fₓ= fcos ∅⇒ 13.8 cos 35.3= 11.26

fy= fsin∅⇒17.6 sin 60.6=15.33

f=√126.79+235.01=√361.7989= 19.02 km

a, c, d, e are all applying about success strategies.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2