Aflowerpot falls off a windowsill and falls past the window below. you may ignore air resistance it takes the pot 0.420 s to pass from the top to the bottom of this window, which is 1.90 m high.1. how far is the top of the window below the windowsill from which the flowerpot fell?

the distance of the top of the window below the windowsill from which the flowerpot fell is 0.31 m

Explanation:

given information:

time, t = 0.420 s

height, h = 1.9 m

the the vertical motion equation:

h = t +

where

h = height (m)

= initial velocity (m/s)

t = time (s)

g = gravitational force (9.8 )

first we calculate the velocity of the flowers pot when it reaches top window

h = t +

1.9 = (0.42) + ()

= (1.9 - ())/0.42

   = 2.47 m/s

now we can find the distance of the windowsil

+ 2gh

v = 0, thus

2gh = -

h = -/2g

  = / (2 x 9.8)

  = 0.31 m

it's a b and