For a certain ideal carnot engine, the hot reservoir is 35°c higher than the cold reservoir. if this engine is to have an efficiency of 20%, what must be the temperature of the hot reservoir?

Temperature of the hot reservoir is 1540K

Explanation:

0.2=({T_c}+308-{T_c})/{T_c}+308

.2({T_c}+61.6=308

0.2{T_c}=246.4

{T_c}=1232

recall from equation 1

{T_h}=308+1232

{T_h}=1540K

asthenosphere and convection

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