A16 lb block rests on a horizontal frictionless surface. a cord attached to the block, running horizontally, passes over a pulley whose diameter is 10 in, to a hanging block weighing 16 lb. the system is released from rest, and the blocks are observed to move 7 ft in 2 s. what is the moment of inertia of the pulley (in slug-feet^2)?

I = 6.2161900319309  slug-feet^2[/tex]

Explanation:

The moment of inertia of an object may simply be stated as a measure of how difficult it is to start it spinning, or to alter an object's spinning motion

The moment of inertia of an object is given by the expression

but in this case we are talking about the moment of inertia of a circular disk, the expression is a bit different

mr^{2}" alt="\frac{1}{2}" />mr^{2}" />

inputting the values given in the expression above

moment of inertia  = 200 lb

the expected outcome should be in slug feet squared

1 slug-feet squared = 32.1740488782426

therefore we need to divide our answer by this value

so

=

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more