Ablock with mass m =6.4 kg is hung from a vertical spring. when the mass hangs in equilibrium, the spring stretches x = 0.28 m. while at this equilibrium position, the mass is then given an initial push downward at v = 5.1 m/s. the block oscillates on the spring without friction.
1)what is the spring constant of the spring?
2)what is the oscillation frequency?
3)after t = 0.42 s what is the speed of the block?
4)what is the magnitude of the maximum acceleration of the block?
5)at t = 0.42 s what is the magnitude of the net force on the block?

Answer

given,

mass of block (m)= 6.4 Kg

spring is stretched to distance, x = 0.28 m

initial velocity = 5.1 m/s

a) computing weight of spring

    k x = m g

      k = 224 N/m

b)

c)  

d)  

e)  

        A = 0.682 m

Force =

          =

F = 94.20 N

c) power lifting, will be your answer.

,

deku ❤

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.