Transverse waves are traveling on a long string that is under a tension of 10.0 n. the equation describing these waves is y(x, t)=( 6.05 cm)sin[( 435 s−1)t−( 45.1 m−1)x]. find the linear mass density of this string.

μ = 0.108 kg/m

Explanation:

Given that

Tension ,T= 10 N

y(x,t)=( 6.05 cm)sin[( 435 s−1)t−( 45.1 m−1)x]

Standard form

Y(x,t)=A sin[ωt−k x]

By compare ,we can say that

ω = 435 s⁻¹

We know that   ω = 2 π f

f=69.23  Hz

k = 45.1 m⁻¹

We know that

λ =0.139  m

We know that the velocity given as

V = f λ

V= 0.139 x 69.23 m/s

V= 9.6 m/s

The linear mass density given as

μ = 0.108 kg/m

This is the mass density.

option number c is the right answer.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2