What buoyant force does a 0.60-kg solid gold crown experience when it is immersed in water? the density of gold is 19.3 × 103 kg/m3 and that of water is 1000 kg/m3.

W = 0.3045 N

Explanation:

given,

mass of the object = 0.6

density of gold = 19.3 x 10³ kg/m³

density of water = 1000 Kg/m³

buoyant force = ?

Volume of the crown=

density = mass/volume

V = 3.108 x 10⁻⁵ m³

W = ρ V g

W = 1000 x 3.108 x 10⁻⁵ x 9.8

W = 0.3045 N

Buoyant force acting on the crown is equal to W = 0.3045 N

d.7.5cm is your answer