Consider a motor that exerts a constant torque of 25.0 nâ‹…m to a horizontal platform whose moment of inertia is 50.0 kgâ‹…m2. assume that the platform is initially at rest and the torque is applied for 12.0 rotations. neglect friction.

W = 1884J

Explanation:

This question is incomplete. The original question was:

Consider a motor that exerts a constant torque of 25.0 N.m to a horizontal platform whose moment of inertia is 50.0kg.m^2 . Assume that the platform is initially at rest and the torque is applied for 12.0rotations . Neglect friction.

How much work W does the motor do on the platform during this process?  Enter your answer in joules to four significant figures.

The amount of work done by the motor is given by:

Where I = 50kg.m^2 and ωo = rad/s. We need to calculate ωf.

By using kinematics:

But we don't have the acceleration yet. So, we have to calculate it by making a sum of torque:

    =>    

Now we can calculate the final velocity:

Finally, we calculate the total work:

Since the question asked to "Enter your answer in joules to four significant figures.":

W = 1884J

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards