Abox of books weighing 325 n moves at a constant velocity across the floor when the box is pushed with a force of 425 n exerted downward at an angle of 35.2 degrees below the horizontal. fink mu, k between the box and the floor

The coefficient of friction between the box and the floor is 0.61.

The given parameters;

The normal force on the box is calculated as follows;

Fₙ = 325 + 425sin(35.2)

Fₙ = 569.8 N

The frictional force on the box is calculated as;

The coefficient of friction between the box and the floor is calculated as follows;

Thus, the coefficient of friction between the box and the floor is 0.61.

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The coefficient of kinetic friction between the box and the floor is 0.60.

Given data:

The weight of box is, W = 325 N.

The magnitude of force on the box is, F = 425 N.

The angle with respect to the horizontal is, .

The frictional force acting on the box provides the linear acceleration to box. Then,

Frictional force is also expressed as,

Here, N is the normal force and its value is, .

Solving as,

Thus, the coefficient of kinetic friction between the box and the floor is 0.60.

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explanation:

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