Ahorizontal cable pulls a 200-kg cart along a horizontal track. the tension in the cable is 500n. starting from rest, how long will it take the cart to reach a speed of 8 m/s? how far will it have gone?

s = 12.8 m

Explanation:

given,                              

mass of the cart = 200 Kg        

tension of the cable = 500 N

initial velocity = 0 m/s                

final velocity = 8 m/s              

using formula                      

F  = mass x acceleration    

500 = 200 x a                    

using equation of motion

v² = u² + 2 as                        

8² = 0² + 2 x 2.5 x s            

64 = 5 s                                  

s = 12.8 m                              

the distance travel used to reach speed of 8 m/s is equal to 12.8 m

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