Encuentra en forma gráfica el peso de un objeto que se encuentra suspendido del techo por 2 cuerdas, las cuales ejercen una fuerza de 320n y 400n y forman un angulo de 80 grados entre si

709.06 N

Explanation:

To do this, you need to do the drawing of this exercise. In the picture below, you have the draw, and the procedure to do this exercise. You need to apply 2nd Newton's law which is:

F = m*a

However, in this case, we only have tension and the weight of the object (As you can see in the picture), and we have no movement, the object it's supposed to be in rest, so, second law becomes this:

F = 0

In this case, we have rod and weight so the forces involving here are those, so second law is like this:

T1y + T2y - W = 0

To get the T1y and T2y, we have the angle so:

T1y = 320 sin80° = 315.14 N

T2y = 400 sin80° = 393.92 N

With these values, replace them and we get:

315.14 + 392.92 - W = 0

709.06 - W = 0

W = 709.06 N

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