Acar start from rest has an acc
0.3 m/s², calculate the velocity and distance
travelled by this car after 2 min
-

Velocity of car after 2mins is 36m/s

Distance travelled after 2mins is 2160m

Explanation:

A car start from rest with acceleration a=0.3

Using equation of motion,

Velocity v is given by :

Distance d is given by

Velocity after time t=2mins=120s is

As car start from rest u=0

Therefore, Velocity of car after 2mins is 36m/s

Distance travelled after 2mins=120s

As car start from rest u=0

Therefore, Distance travelled after 2mins is 2160m

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