a football is kicked at an angle,
of 37° above the horizontal,
with a velocity of 20m/s
give the following:
-initial velocity
- amount of time in the air
- maximum height
- initial x velocity
- the distance traveled in the x direction

The initial velocity of the ball is, u = 20 m/s

Hence, the amount of the time in air, = 2.45 s

Hence, the maximum height of the football is,   =  7.39 m

The x velocity of the football is, Vₓ = 15.97 m/s

Hence, the distance traveled in the x direction is, S = 39.25 m

Explanation:

Given data,

The projected angle of the football to the horizontal, Ф = 37°

The velocity of the ball, v = 20 m/s

The initial velocity of the ball is, u = 20 m/s

The amount of time in air,

              = 2.45 s

Hence, the amount of the time in air, = 2.45 s

The maximum height,

                =  7.39 m

Hence, the maximum height of the football is,   =  7.39 m

The initial horizontal velocity,

                       Vₓ = V cos Ф

                             = 20 x 0.7986

                             = 15.97 m/s

The x velocity of the football is, Vₓ = 15.97 m/s

The distance traveled in the x direction

                   S = 39.25 m

Hence, the distance traveled in the x direction is, S = 39.25 m                            

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.